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4x^2-6=346
We move all terms to the left:
4x^2-6-(346)=0
We add all the numbers together, and all the variables
4x^2-352=0
a = 4; b = 0; c = -352;
Δ = b2-4ac
Δ = 02-4·4·(-352)
Δ = 5632
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{5632}=\sqrt{256*22}=\sqrt{256}*\sqrt{22}=16\sqrt{22}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-16\sqrt{22}}{2*4}=\frac{0-16\sqrt{22}}{8} =-\frac{16\sqrt{22}}{8} =-2\sqrt{22} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+16\sqrt{22}}{2*4}=\frac{0+16\sqrt{22}}{8} =\frac{16\sqrt{22}}{8} =2\sqrt{22} $
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